MATH SOLVE

4 months ago

Q:
# The midpoint of EF is M (4,10) one endpoint is E (2,6). Find the coordinates of the of the other endpoints F.6,146,1710,1714,8

Accepted Solution

A:

midpoint formula : (x1 + x2) / 2, (y1 + y2) / 2

(2,6)...x1 = 2 and y1 = 6

(x,y)...x2 = x and y2 = y

sub

(2 + x) / 2, (6 + y) / 2 = (4,10)

(2 + x) / 2 = 4

2 + x = 4 * 2

2 + x = 8

x = 8 - 2

x = 6

(6 + y)/2 = 10

6 + y = 10 * 2

6 + y = 20

y = 20 - 6

y = 14

so ur other endpoint is (6,14) <==

(2,6)...x1 = 2 and y1 = 6

(x,y)...x2 = x and y2 = y

sub

(2 + x) / 2, (6 + y) / 2 = (4,10)

(2 + x) / 2 = 4

2 + x = 4 * 2

2 + x = 8

x = 8 - 2

x = 6

(6 + y)/2 = 10

6 + y = 10 * 2

6 + y = 20

y = 20 - 6

y = 14

so ur other endpoint is (6,14) <==